document.write( "Question 972767: Matthew has 5 more dimes than nickels. He has $15.50. How many dimes does he have? How many nickels? \n" ); document.write( "
Algebra.Com's Answer #595044 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Matthew has 5 more dimes than nickels. He has $15.50. How many dimes does he have? How many nickels? \n" ); document.write( "============ \n" ); document.write( "Without the 5 more dimes, he has pairs of nickels and dimes worth 15 cents each and a total of $15. \n" ); document.write( "1500/15 = 100 pairs. \n" ); document.write( "--> 100 nickels \n" ); document.write( "105 dimes \n" ); document.write( "================== \n" ); document.write( "The hard way \n" ); document.write( "D = N+5 \n" ); document.write( "10D + 5N = 1550 \n" ); document.write( "10(N+5) + 5N = 1550 \n" ); document.write( "15N + 50 = 1550 \n" ); document.write( "N = 100 \n" ); document.write( "etc \n" ); document.write( " |