document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82911>Question 82911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Evaluate (-x) ^ 2 which means (-x) to the power of 2 or square and compare this to - (x^2). Use x=5.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59504 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Evaluate (-x) ^ 2 which means (-x) to the power of 2 or square and compare this to - (x^2). Use x=5.<BR>\n" );
document.write( "(-x)^2 = (-x)(-x) = (-1)(-1)(x)(x) = x^2<BR>\n" );
document.write( "All values when plugged in for x will be positive.<BR>\n" );
document.write( "-(x)^2 = -1(x)(x) = -x^2<BR>\n" );
document.write( "All values when plugged in for x will be negative.<BR>\n" );
document.write( "(-x)^2 = (-5)^2 = 25<BR>\n" );
document.write( "-(x)^2 = -(5)^2 = -25<BR>\n" );
document.write( "Red: (-x)^2<BR>\n" );
document.write( "Green: -(x)^2<BR>\n" );
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