document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972797>Question 972797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roy is twice as old as Joan, and in 3 years the sum of their ages will be 21 years. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595029 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let Roy's age be x and Joan's age be y, then<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "x+3 + y+3 = 21<BR>\n" );
document.write( "substitute 2y for x<BR>\n" );
document.write( "2y+3 + y+3 = 21<BR>\n" );
document.write( "3y + 6 = 21<BR>\n" );
document.write( "subtract 6 from both sides of =<BR>\n" );
document.write( "3y = 15<BR>\n" );
document.write( "divide both sides of = by 3<BR>\n" );
document.write( "y = 5 and x = 10<BR>\n" );
document.write( "Roy is 10 and Joan is 5<BR>\n" );
document.write( "****************************<BR>\n" );
document.write( "check answer<BR>\n" );
document.write( "10+3 + 5+3 = 21<BR>\n" );
document.write( "13 + 8 = 21<BR>\n" );
document.write( "21 = 21<BR>\n" );
document.write( "our answer checks </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );