document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972640>Question 972640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are two different copper alloys of total weight 50 kilograms. the first contains 40%less copper than the second one. determine the percentage of copper in first alloy . if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594997 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are two different copper alloys of total weight 50 kilograms<BR>\n" );
document.write( "let x = amt of the 1st alloy<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(50-x) amt of the 2nd alloy<BR>\n" );
document.write( ":<BR>\n" );
document.write( " the first contains 40%less copper than the second one. determine the<BR>\n" );
document.write( "Use the decimal equiv of percent <BR>\n" );
document.write( "\"percentage of copper in first alloy if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy?\"<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2Fx ALIGN=MIDDLE  ALT=\"6%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" > = percent copper in the 1st alloy (in decimal form)<BR>\n" );
document.write( "and<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F%28%2850-x%29%29 ALIGN=MIDDLE  ALT=\"12%2F%28%2850-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = percent copper in the 2nd alloy<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"the first contains 40%less copper than the second one.\",<BR>\n" );
document.write( "40% less means the 1st alloy copper is .6 of the 2nd alloy, therefore:<BR>\n" );
document.write( ".6*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F%28%2850-x%29%29 ALIGN=MIDDLE  ALT=\"12%2F%28%2850-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2Fx ALIGN=MIDDLE  ALT=\"6%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7.2%2F%28%2850-x%29%29 ALIGN=MIDDLE  ALT=\"7.2%2F%28%2850-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2Fx ALIGN=MIDDLE  ALT=\"6%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "7.2x = 6(50-x)<BR>\n" );
document.write( "7.2x = 300 - 6x<BR>\n" );
document.write( "7.2x + 6x = 300<BR>\n" );
document.write( "13.2x = 22.73 kg, the amt of the 1st alloy<BR>\n" );
document.write( "then<BR>\n" );
document.write( "50-22.73 = 27.27 kg, the amt of the 2nd alloy<BR>\n" );
document.write( "\"what is the percentage of copper in second alloy?\"<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F27.27 ALIGN=MIDDLE  ALT=\"12%2F27.27\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 100 = 44% copper in the 2nd alloy<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check this by finding the percent copper in the 1st alloy<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F22.73 ALIGN=MIDDLE  ALT=\"6%2F22.73\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 100 = 26.4%<BR>\n" );
document.write( "Find the relationship to the copper in te 2nd alloy<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=26.4%2F44 ALIGN=MIDDLE  ALT=\"26.4%2F44\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 100 = 60% which is 40% less than the 2nd alloy copper<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );