document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972729>Question 972729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> uThe longer leg of a right triangle is 1 cm less than twice the shorter leg. The hypotenuse is 17 cm long.Find the length of each leg. Hint: What theorem will you need to solve this problem, and what type of equation will you end up solving? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594986 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> shorter leg is x<BR>\n" );
document.write( "longer leg is 2x-1<BR>\n" );
document.write( "Pythagorean theorem\r<BR>\n" );
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document.write( "x^2 +(2x-1)^2=17^2\r<BR>\n" );
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document.write( "x^2 + 4x^2-4x +1=289\r<BR>\n" );
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document.write( "Quadratic equation<BR>\n" );
document.write( "5x^2 -4x -288=0\r<BR>\n" );
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document.write( "(5x^2+36) * (x-8)=0\r<BR>\n" );
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document.write( "x=-36/5  (not sensible here)<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "2x-1=15<BR>\n" );
document.write( "This is an 8,15,17 right triangle </SPAN>\n" );
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