document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972730>Question 972730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if tan 0 = -(3/4) and 0 line in the 2th quadrant, the value of csc 0 is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594980 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  if tan 0 = -(3/4) and 0 line in the 2th quadrant, the value of csc 0 is?<BR>\n" );
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document.write( "Since tan = y/x, y = 3 and x = -4 in QII<BR>\n" );
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document.write( "Then r = sqrt(3^2+4^2) = 5<BR>\n" );
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document.write( "Ans: csc(t) = r/y = 5/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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