document.write( "Question 972711: I have an equation of a semi-ellipse that I found from the graph. I need to get it into y= form from standard form. The equation right from the graph is ((x-10)^2)/64 + (y^2)/256 = 1\r
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document.write( "If possible, please show work as well. Thank you very much! \n" );
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Algebra.Com's Answer #594971 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Start by moving the x to the other side \n" ); document.write( "[y^2/256]= 1- [(x-10)^2/64] Now multiply by 256 and then take the square root.\r \n" ); document.write( "\n" ); document.write( "Y^2= 256-4(x-10)^2 \n" ); document.write( "Y=+/- sqrt [256-4(x-10)^2] I will call this (1); Notice that it is a difference of squares.\r \n" ); document.write( "\n" ); document.write( "= sqrt {(16+2(x-10)) (16-(2(x-10))} sqrt{ (2x-4) (-2x+36)} I will call this (2) \n" ); document.write( "I graphed (1) below, but (2) graphs the same on a TI-83.\r \n" ); document.write( "\n" ); document.write( " |