document.write( "Question 972698: The capacity of a car radiator is 18 quarts. If it is currently filled with a 20% antifreeze solution, how many quarts must be drained and replaced with a 100% antifreeze solution to give 18 quarts of a 39% antifreeze solution?
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Algebra.Com's Answer #594950 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+.2%2A18+=+3.6+\" quarts of antifreeze at beginning
\n" ); document.write( "Let \"+x+\" = quarts of antifreeze solution to be drained off
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\n" ); document.write( "Note that you start with \"+18+\" quarts
\n" ); document.write( "and you end up with \"+18+\" quarts
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\n" ); document.write( "You are draining off a 20% solution, so you are
\n" ); document.write( "draining off \"+.2x+\" quarts of the pure antifreeze
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\n" ); document.write( "You replace the solution drained off with \"+x+\"
\n" ); document.write( "quarts of pure antifreeze
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\n" ); document.write( "I can now say:
\n" ); document.write( "\"+%28+3.6+-+.2x+%2B+x+%29+%2F+18+=+.39+\"
\n" ); document.write( "\"+%28+3.6+%2B+.8x+%29+%2F+18+=+.39+\"
\n" ); document.write( "\"+3.6+%2B+.8x+=+.39%2A18+\"
\n" ); document.write( "\"+.8x+=+7.02+-+3.6+\"
\n" ); document.write( "\"+.8x+=+3.42+\"
\n" ); document.write( "\"+x+=+4.275+\"
\n" ); document.write( "4.275 quarts of solution must be drained off and replaced
\n" ); document.write( "with 100% pure antifreeze
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\n" ); document.write( "check:
\n" ); document.write( "\"+%28+3.6+%2B+.8x+%29+%2F+18+=+.39+\"
\n" ); document.write( "\"+%28+3.6+%2B+.8%2A4.275+%29+%2F+18+=+.39+\"
\n" ); document.write( "\"+%28+3.6+%2B+3.42+%29+%2F+18+=+.39+\"
\n" ); document.write( "\"+7.02+=+.39%2A18+\"
\n" ); document.write( "\"+7.02+=+7.02+\"
\n" ); document.write( "OK
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