document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972612>Question 972612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You invest $4,200 in an account that pays an interest rate of 6.5%, compounded continously. Calculate the balance of your account after 10 years. Round your answer to the nearest hundredth.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594919 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=4200*e^(.065*10)   Pexp ^rt, and r is a decimal\r<BR>\n" );
document.write( "\n" );
document.write( "A=4200*e^.65\r<BR>\n" );
document.write( "\n" );
document.write( "A=$8045.27\r<BR>\n" );
document.write( "\n" );
document.write( "This is almost doubling, and the rule of 72 would predict doubling in 11 years, so the answer makes sense. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );