document.write( "Question 972566: I am now four times as old as my sister. When I am four times as old as I am now, my sister will still be less than thirty years old. How old is she now?\r
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Algebra.Com's Answer #594890 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
b,s brother, sister;
\n" ); document.write( "x, more years;\r
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\n" ); document.write( "\n" ); document.write( "\"b=4s\", \"4b=%28s%2Bx%29%3C30\".\r
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\n" ); document.write( "\n" ); document.write( "\"4%284s%29=s%2Bx%3C30\"
\n" ); document.write( "\"16s=s%2Bx%3C30\"
\n" ); document.write( "This looks like two simultaneous statements in variables s and x.
\n" ); document.write( "\"system%2816s=s%2Bx%2Cs%2Bx%3C30%29\"
\n" ); document.write( "\"system%2815s=x%2Cs%3C30-x%29\"
\n" ); document.write( "\"s%3C30-%2815s%29\"
\n" ); document.write( "\"s%3C30-15s\"
\n" ); document.write( "\"s%2B15s%3C30\"
\n" ); document.write( "\"16s%3C30\"
\n" ); document.write( "\"8s%3C15\"
\n" ); document.write( "\"s%3C15%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Sister could be between 0 years and 1 year 10.5 months, exclusive.
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