document.write( "Question 972484: Find the vertices and foci of the hyperbola. Draw the graph.
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document.write( "y^2/25 - x^2/21=1\r
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document.write( "x^2/9 - y^2/16=1 \n" );
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Algebra.Com's Answer #594884 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertices and foci of the hyperbola. Draw the graph. \n" ); document.write( "y^2/25 - x^2/21=1 \n" ); document.write( "center: (0,0) \n" ); document.write( "a^2=25 \n" ); document.write( "a=5 \n" ); document.write( "vertices: (0, 0±a)= (0, 0±5)=(0,-5) and (0,5) \n" ); document.write( "b^2=21 \n" ); document.write( "c^2=a^2+b^2=25+21=46 \n" ); document.write( "c=√46≈6.8 \n" ); document.write( "foci: (0, 0±c)= (0, 0±6.8)=(0,-6.8) and (0,6.8) \n" ); document.write( "see graph below: \n" ); document.write( "y=(25x^2/21+25)^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "x^2/9 - y^2/16=1 \n" ); document.write( "center: (0,0) \n" ); document.write( "a^2=9 \n" ); document.write( "a=3 \n" ); document.write( "vertices: (0±a, 0)= (0±3, 0)=(-3, 0) and (4, 0) \n" ); document.write( "b^2=16 \n" ); document.write( "c^2=a^2+b^2=9+16=25 \n" ); document.write( "c=5 \n" ); document.write( "foci:(0±c, 0)= (0±5, 0)=(-5, 0) and (5, 0) \n" ); document.write( "see graph below: \n" ); document.write( "y=(16x^2/9-16)^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( " |