document.write( "Question 972570: At 12-noon flight 237 leaves Chicago headed due south and traveling at a rate of r miles per hour. At 12-noon a second flight, flight 875, left Chicago from a different runway headed due east and traveling 40 miles per hour slower than flight 237. At 3:00pm the planes are 600 miles apart. How fast is flight 237 traveling? \n" ); document.write( "
Algebra.Com's Answer #594880 by lwsshak3(11628)\"\" \"About 
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At 12-noon flight 237 leaves Chicago headed due south and traveling at a rate of r miles per hour. At 12-noon a second flight, flight 875, left Chicago from a different runway headed due east and traveling 40 miles per hour slower than flight 237. At 3:00pm the planes are 600 miles apart. How fast is flight 237 traveling?
\n" ); document.write( "***
\n" ); document.write( "both planes have been flying for 3 hours(travel time)
\n" ); document.write( "let r=speed of flight 237
\n" ); document.write( "r-40=speed of flight 875
\n" ); document.write( "distance =speed*travel time
\n" ); document.write( "..
\n" ); document.write( "3r=distance traveled by flight 237(1 leg of right triangle)
\n" ); document.write( "3(r-40)distance traveled by flight 875(other leg of right triangle)
\n" ); document.write( "600=hypotenuse of right triangle
\n" ); document.write( "By the Pythagorean Theorem:
\n" ); document.write( "600^2=9r^2+9(r-40)^2
\n" ); document.write( "600^2=9r^2+9(r^2-80r+1600)
\n" ); document.write( "360000=9r^2+9r^2-720r+14400)
\n" ); document.write( "18r^2-720r-345600=0
\n" ); document.write( "divide by 18
\n" ); document.write( "r^2-40r-19200=0
\n" ); document.write( "(r-160)(r+120)=0
\n" ); document.write( "r=160
\n" ); document.write( "How fast is flight 237 traveling? 160 mph \n" ); document.write( "
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