document.write( "Question 972570: At 12-noon flight 237 leaves Chicago headed due south and traveling at a rate of r miles per hour. At 12-noon a second flight, flight 875, left Chicago from a different runway headed due east and traveling 40 miles per hour slower than flight 237. At 3:00pm the planes are 600 miles apart. How fast is flight 237 traveling? \n" ); document.write( "
Algebra.Com's Answer #594878 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Let r=the rate of Flight 237 \n" ); document.write( "Between noon and 3:00pm (3 hours), Flight 237 travels 3hrs(r) miles. \n" ); document.write( "Flight 875 travels 3hrs(r-40mph) \n" ); document.write( "These two distances form a right triangle with hypotenuse=600 miles. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The rate of Flight 237 was 160 mph. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "The rate of Flight 237 was 160 mph, so its distance was 480 miles. \n" ); document.write( "The rate of Flight 875 was 120 mph, so its distance was 360 miles . \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |