document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972528>Question 972528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve secx - square root of 2 = 0 algebraically for all values of x in 0 degrees less than or equal to x less than 360 degrees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594844 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve secx - square root of 2 = 0 algebraically for all values of x in 0 degrees less than or equal to x less than 360 degrees.<BR>\n" );
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document.write( "secx-&#8730;2=0<BR>\n" );
document.write( "secx=&#8730;2<BR>\n" );
document.write( "1/cosx=&#8730;2<BR>\n" );
document.write( "cosx=1/&#8730;2=&#8730;2/2<BR>\n" );
document.write( "x=45&#730;, 315&#730; </SPAN>\n" );
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