document.write( "Question 972538: Solve \"ln+%28%28x-3%29%28x%2B2%29%29+=+0\" for x. The only solutions of the form \"x+=+%28%281%2B+sqrtb%29%2F2%29\" what is b?\r
\n" ); document.write( "\n" ); document.write( "What I did: ln((x-3)(x+2))
\n" ); document.write( " ln(x^2 -x-6)
\n" ); document.write( " a= 1 b = -1 c = -6 \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%281%29+%2B-+sqrt%28%28-1%29%5E2+-+4%28a%29%28-6%29%29%29%2F2%281%29\"\r
\n" ); document.write( "\n" ); document.write( "that would come out to \"x+=+%281+%2B-+sqrt%2825%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Where did I go wrong?
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Algebra.Com's Answer #594836 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
You need to convert the problem to a quadratic form. You had an ln(quadratic form). One thing to do is to graph it, and just see what it looks like.\r
\n" ); document.write( "\n" ); document.write( "The way I like to deal with ln is raise everything to the e power. Then you have a quadratic =1, and you can deal with it accordingly.\r
\n" ); document.write( "\n" ); document.write( "Raise everything to the e power
\n" ); document.write( "(x-3)(x+2)=1\r
\n" ); document.write( "\n" ); document.write( "x^2-x-7=0
\n" ); document.write( "[1 +/- sqrt (1+28)]/2 \r
\n" ); document.write( "\n" ); document.write( "x=3.19 and -2.19\r
\n" ); document.write( "\n" ); document.write( "b=28\r
\n" ); document.write( "\n" ); document.write( "substitute in ln (0.19)(5.19) is very close to 1, and ln (1)=0\r
\n" ); document.write( "\n" ); document.write( "ln (-5.19)((-0.19) is the same,\r
\n" ); document.write( "\n" ); document.write( "\"+graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2Cln%28%28x-3%29%28x%2B2%29%29%29\"
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