document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82898>Question 82898</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130519669/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> please help me with this problem its a story problem and I apoligize if its under the wrong heading:\r<BR>\n" );
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document.write( "If a certain number, two thirds of it, half of it, and a seventh of it are added together, the result is 97. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59482 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+2/3x+1/2x+1/7x=97 find a common denominator so we can add the fractions:<BR>\n" );
document.write( "7*2*3=42 so we change every fraction to have a denominator of 42 & add the numerators thus:<BR>\n" );
document.write( "2/3=2*14/42=28/42<BR>\n" );
document.write( "1/2=1*21/42=21/42<BR>\n" );
document.write( "1/7=1*6/42=6/42<BR>\n" );
document.write( "(42+28+21+6)x/42=97<BR>\n" );
document.write( "97x/42=97 now we cross multiply:<BR>\n" );
document.write( "97x=42*97<BR>\n" );
document.write( "x=42*97/97<BR>\n" );
document.write( "x=42 answer for the original number.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "42+42/2+42/3+42/7=97<BR>\n" );
document.write( "42+28+21+6=97<BR>\n" );
document.write( "97=97<BR>\n" );
document.write( " </SPAN>\n" );
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