document.write( "Question 972441: Seven times a two digit number is equal to four times the number obtained by reversing the digits. If the difference between the two digits is 3, find the number.
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Algebra.Com's Answer #594783 by MathTherapy(10552) $\"\"$ $\"About$

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Seven times a two digit number is equal to four times the number obtained by reversing the digits. If the difference between the two digits is 3, find the number.
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Let the tens and units digits be T and U, respectively
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document.write( "Then original number is: 10T + U
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document.write( "Reversed number is: 10U + T
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document.write( "Seven (7) times the original number is (=) ONLY 4 times the reversed number, which suggests that the 
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document.write( "original number is SMALLER than the reversed number. As the original number is SMALLER than the reversed
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document.write( "number, U, or the units digit is LARGER than the tens digit. Therefore, we get the following system of equations: 
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document.write( "7(10T + U) = 4(10U + T)
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document.write( "U – T = 3\r
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document.write( "Solve this system for T: the tens digit, and U: the units or ones digit. You'll then have the ORIGINAL NUMBER. \n" );
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