document.write( "Question 82898This question is from textbook Algebra 1
\n" ); document.write( ": please help me with this problem its a story problem and I apoligize if its under the wrong heading:\r
\n" ); document.write( "\n" ); document.write( "If a certain number, two thirds of it, half of it, and a seventh of it are added together, the result is 97. What is the number?
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Algebra.Com's Answer #59478 by sofiyacherni(99)\"\" \"About 
You can put this solution on YOUR website!
ok call your number x\r
\n" ); document.write( "\n" ); document.write( "then \"x%2B2x%2F3%2B1x%2F2%2B1x%2F7=97\" find common denominator which will divide by 3, 2 and 7.
\n" ); document.write( "The smallest one i found is 42 so
\n" ); document.write( "add all the numbers together, you get
\n" ); document.write( "\"%2842x%2B28x%2B21x%2B6x%29%2F42=97%2F1\" cross multiply
\n" ); document.write( "\"42x%2B28x%2B21x%2B6x=42%2897%29\" now add all the numbers with x, you get
\n" ); document.write( "\"97x=42%2897%29\" divide both sides by 97 and you get
\n" ); document.write( "x=42 :)\r
\n" ); document.write( "\n" ); document.write( "that's your number!
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