document.write( "Question 972462: A number is doubled, and then seven is added. When the result is divided by forty, the quotient is two and the remainder is thirty-three. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #594769 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
A number
That's N
is doubled,
That's 2N
and then seven is added.
That's 2N + 7
When the result is divided by forty,
That's \"%282N%2B7%29%2F40\"
the quotient is two and the remainder is thirty-three.
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document.write( "That says \"%282N%2B7%29%2F40\"\"%22%22=%22%22\"\"2%2633%2F40\"\r\n" );
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document.write( "That's because you put the remainder over the divisor \r\n" );
document.write( "when you finish dividing. The divisor is 40 because that's\r\n" );
document.write( "what we divided by.\r\n" );
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document.write( "We change the mixed number to an improper fraction \"113%2F40\"\r\n" );
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document.write( "Now we have this equation:\r\n" );
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document.write( "\"%282N%2B7%29%2F40\"\"%22%22=%22%22\"\"113%2F40\"\r\n" );
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document.write( "We multiply both sides by 40, and get: \r\n" );
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document.write( "2N + 7 = 113\r\n" );
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document.write( "We subtract 7 from both sides:\r\n" );
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document.write( "    2N = 106\r\n" );
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document.write( "We divide both sides by 2\r\n" );
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document.write( "    N = 53\r\n" );
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document.write( "-------\r\n" );
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document.write( "Now we check
A number
That's 53
is doubled,
That's 106
and then seven is added.
That's 106 + 7 = 113
When the result is divided by forty,
That's this division\r\n" );
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document.write( "     2\r\n" );
document.write( "40)113\r\n" );
document.write( "    80\r\n" );
document.write( "    33\r\n" );
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the quotient is two and the remainder is thirty-three.
It checks.\r\n" );
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document.write( "Edwin
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