document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972441>Question 972441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Seven times a two  digit  number  is equal to four times the number  obtained  by reversing  the digits. If the difference  between  the two  digits  is 3, find the number. <BR>\n" );
document.write( "Plzzzzzz solve it.......<BR>\n" );
document.write( "Thank  you. ...!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594758 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let xy be the two digit number, now<BR>\n" );
document.write( "xy = 10x + y and<BR>\n" );
document.write( "x - y = 3 then<BR>\n" );
document.write( "x = y+3<BR>\n" );
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document.write( "7(xy) = 4(yx)<BR>\n" );
document.write( "7(10x+y) = 4(10y+x)<BR>\n" );
document.write( "now substitute y+3 for x<BR>\n" );
document.write( "7(10(y+3)+y) = 4(10y+y+3)<BR>\n" );
document.write( "7(10y+30+y) = (40y+4y+12)<BR>\n" );
document.write( "77y+210 = 44y+12<BR>\n" );
document.write( "33y = -198<BR>\n" );
document.write( "y = -6<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "xy = -36<BR>\n" );
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document.write( "check answer<BR>\n" );
document.write( "7(-36) = 4(-63)<BR>\n" );
document.write( "-252 = -252<BR>\n" );
document.write( "answer checks<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );