document.write( "Question 972433: Please help me solve this equation by substitution.\r
\n" ); document.write( "\n" ); document.write( " -5x + 3y = -5, -7x - 5y = -7\r
\n" ); document.write( "\n" ); document.write( "I keep getting a crazy fractional answer, and I don't think it's correct! Thank you! \n" ); document.write( "
Algebra.Com's Answer #594747 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "-5x+3y=-5 Add 5x to each side.(Equation 1)
\n" ); document.write( "3y=5x-5 Divide each side by 3.
\n" ); document.write( "y=(5x-5)/3 Use this to substitute for y in Equation 2
\n" ); document.write( ".
\n" ); document.write( "-7x-5y=-7 Substitute for y (Equation 2)
\n" ); document.write( "-7x-5((5x-5)/3)=-7
\n" ); document.write( "-7x+(-25x+25)/3=-7 Multiply each side by 3.
\n" ); document.write( "-21x-25x+25=-21 Subtract 25 from each side.
\n" ); document.write( "-46x=-46 Divide each side by -46.
\n" ); document.write( "x=1
\n" ); document.write( ".
\n" ); document.write( "-5x+3y=-5 Put in value for x.
\n" ); document.write( "-5(1)+3y=-5
\n" ); document.write( "-5+3y=-5 Add 5 to each side.
\n" ); document.write( "3y=0 Divide each side by 3
\n" ); document.write( "y=0
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "-7x-5y=-7 Put in values.
\n" ); document.write( "-7(1)-5(0)=-7
\n" ); document.write( "-7-0=-7
\n" ); document.write( "-7=-7
\n" ); document.write( " \n" ); document.write( "
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