document.write( "Question 972299: Paul travels from a to b at an average speed of 90 km/h
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document.write( "He travels for \"T\" hours
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document.write( "Mary travels the same journey at an average speed of 70 km/h
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document.write( "She travels for 1 hour longer than Paul.
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document.write( "what is the value of T? \n" );
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Algebra.Com's Answer #594724 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Paul travels from a to b at an average speed of 90 km/h \n" ); document.write( "He travels for \"T\" hours \n" ); document.write( "Mary travels the same journey at an average speed of 70 km/h \n" ); document.write( "She travels for 1 hour longer than Paul. \n" ); document.write( "what is the value of T? \n" ); document.write( ": \n" ); document.write( "T = Paul's travel time \n" ); document.write( "then \n" ); document.write( "(t+1) = Mary's travel time (traveled 1 hr longer)\r \n" ); document.write( "\n" ); document.write( "Write a distance equation: dist = speed * time \n" ); document.write( "Paul's dist = Mary's dist \n" ); document.write( "90t = 70(t+1) \n" ); document.write( "90t = 70t + 70 \n" ); document.write( "90t - 70t = 70 \n" ); document.write( "20t = 70 \n" ); document.write( "t = 70/20 \n" ); document.write( "t = 3.5 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the distance each traveled, should be the same \n" ); document.write( "90*3.5 = 315 mi \n" ); document.write( "70*4.5 = 315 mi \n" ); document.write( " |