document.write( "Question 82904: Can someone please help me with this one?
\n" ); document.write( "Complete the ordered pairs for the equation 2x + y = 10.
\n" ); document.write( " (5, ), ( , 10), ( , –2), (0, )
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Algebra.Com's Answer #59472 by sofiyacherni(99)\"\" \"About 
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Can someone please help me with this one?
\n" ); document.write( "Complete the ordered pairs for the equation 2x + y = 10.
\n" ); document.write( " (5, ), ( , 10), ( , –2), (0, ) \r
\n" ); document.write( "\n" ); document.write( "ok, in an ordered pair the first value is always x value, and second is y value
\n" ); document.write( "so in the first one x=5, thus you have to get y to one side of the equation by itself, you do so by subtracting 2x from both sides
\n" ); document.write( "so 2x-2x+y=10-2x then
\n" ); document.write( "y=10-2x but we already know that x=5, thus y=10-2(5)=10-10=0
\n" ); document.write( "so your first pair is (5,0) because when x=5, y=0
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\n" ); document.write( "next one is opposite, you have y=10 you have to find x
\n" ); document.write( "so 2x=10-y=10-10=0
\n" ); document.write( "then x=0
\n" ); document.write( "so second pair is (0,10)
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\n" ); document.write( "y=-2
\n" ); document.write( "then 2x=10-(-2)=10+2=12
\n" ); document.write( "so 2x=12
\n" ); document.write( "divide both sides by 2 so you can get x by itself and you get
\n" ); document.write( "x=6 so next pair is (6,-2)
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\n" ); document.write( "the last one is x=0
\n" ); document.write( "then 2(0)+y=10 anything times 0 is 0 so
\n" ); document.write( "y=10
\n" ); document.write( "(0,10)\r
\n" ); document.write( "\n" ); document.write( "good luck
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