document.write( "Question 972369: a rectangle pool has an area of 800 ft^2. the length is 10 feet longer than the width. find the dimensions of the pool. solve by completing the square. round answers to the nearest tenth of a foot. \n" ); document.write( "
Algebra.Com's Answer #594710 by Boreal(15235)\"\" \"About 
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width=x
\n" ); document.write( "length=x+10\r
\n" ); document.write( "\n" ); document.write( "x(x+10)=800 ft^2\r
\n" ); document.write( "\n" ); document.write( "x^2 + 10 x= 800 ft^2.\r
\n" ); document.write( "\n" ); document.write( "x^2 +10x +25= 825
\n" ); document.write( "(x+5)^2=825\r
\n" ); document.write( "\n" ); document.write( "X+5+= +sqrt (825)
\n" ); document.write( "x=-5 +sqrt (825)=-5 +28.72=23.7 ft.\r
\n" ); document.write( "\n" ); document.write( "Check: 23.7ft width * 33.7ft length=798.69, which is in rounding error of 800 ft^2.
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