document.write( "Question 82890: solve the system of equations by sustitution\r
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document.write( "3x+4y=-20
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document.write( "x+y=-6 \n" );
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Algebra.Com's Answer #59468 by afphrodietic(3)![]() ![]() ![]() You can put this solution on YOUR website! let 3x+4y=-20 be the first equation \n" ); document.write( "and x+y=-6 the second equation.\r \n" ); document.write( "\n" ); document.write( "then, the second equation becomes x=-6-y. \n" ); document.write( "plug it in the first equation.\r \n" ); document.write( "\n" ); document.write( "3(-6-y)+4y=-20 \n" ); document.write( "-18-3y+4y=-20 \n" ); document.write( "-18+y=-20 \n" ); document.write( "y=-20+18 \n" ); document.write( "y=-2\r \n" ); document.write( "\n" ); document.write( "and\r \n" ); document.write( "\n" ); document.write( "x+(-2)=-6 \n" ); document.write( "x-2=-6 \n" ); document.write( "x=-6+2 \n" ); document.write( "x=-4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, check:\r \n" ); document.write( "\n" ); document.write( "3(-4)+4(-2)=-20 \n" ); document.write( "-12+(-8)=-20 \n" ); document.write( "-12-8=-20 \n" ); document.write( "-20=-20 \n" ); document.write( " |