document.write( "Question 972335: Solve. |x²+6| = 5x \n" ); document.write( "

Algebra.Com's Answer #594677 by Edwin McCravy(20060) $\"\"$ $\"About$

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Solve. |x²+6| = 5x
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document.write( "Since x²+6 is always positive we do not need the absolute values,\r\n" );
document.write( "however we must restrict the right side 5x to always be positive\r\n" );
document.write( "too.  5x > 0, therefore x > 0\r\n" );
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document.write( "    |x²+6| = 5x   x > 0\r\n" );
document.write( "      x²+6 = 5x\r\n" );
document.write( "   x²-5x+6 = 0\r\n" );
document.write( "(x-2)(x-3) = 0\r\n" );
document.write( "x-2=0; x-3=0\r\n" );
document.write( "  x=2;   x=3\r\n" );
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document.write( "They both came out positive so we do not need to say x > 0 or to\r\n" );
document.write( "discard a solution.  Both are solutions:\r\n" );
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document.write( "Edwin

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