document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972317>Question 972317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let (-4,-1) be a point on the terminal side of an angle theta in standard position. Draw the angle then find the 6 trig ratios as well as the measure of angle theta. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594667 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let (-4,-1) be a point on the terminal side of an angle theta in standard position. Draw the angle then find the 6 trig ratios as well as the measure of angle theta. <BR>\n" );
document.write( "------<BR>\n" );
document.write( "x = -4<BR>\n" );
document.write( "y = -1<BR>\n" );
document.write( "r = sqrt[4^2 + 1^2] = sqrt(17)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "sin(t) = y/r = -1/sqrt(17)<BR>\n" );
document.write( "cos(t) = x/r = -4/sqrt(17)<BR>\n" );
document.write( "tan(t) = y/x = 1/4<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "csc(t) = -sqrt(17)<BR>\n" );
document.write( "sec(t) = -sqrt(17)/4<BR>\n" );
document.write( "cot(t) = 4<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );