document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972319>Question 972319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=-1<BR>\n" );
document.write( "6x+y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594656 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=-1<BR>\n" );
document.write( "6x+y=3\r<BR>\n" );
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document.write( "Double second equation and add\r<BR>\n" );
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document.write( "3x-2y=-1<BR>\n" );
document.write( "12x+2y=6\r<BR>\n" );
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document.write( "15x=5<BR>\n" );
document.write( "x=1/3\r<BR>\n" );
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document.write( "Substitute into second equation<BR>\n" );
document.write( "6(1/3)+y =3<BR>\n" );
document.write( "y=1\r<BR>\n" );
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document.write( "(1/3,1)\r<BR>\n" );
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document.write( "Check into first equation<BR>\n" );
document.write( "3(1/3)-2(1)=1-2=-1 </SPAN>\n" );
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