document.write( "Question 82875: Solve 5x^2 + 1= 5x \n" ); document.write( "
Algebra.Com's Answer #59462 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"5x%5E2+%2B+1=+5x\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2+%2B+1+-5x=+0\" Subtract 5x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2+-5x%2B+1+=+0\" Rearrange the terms in \"ax%5E2%2Bbx%2Bc\" form\r
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\n" ); document.write( "\n" ); document.write( "Now we can use the quadratic formula to solve for x:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"5x%5E2%2B-5x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-5%29%5E2-4%2A5%2A1=5\".
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\n" ); document.write( " Discriminant d=5 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--5%2B-sqrt%28+5+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+5+%29%29%2F2%5C5+=+0.723606797749979\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-5%29-sqrt%28+5+%29%29%2F2%5C5+=+0.276393202250021\"
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\n" ); document.write( " Quadratic expression \"5x%5E2%2B-5x%2B1\" can be factored:
\n" ); document.write( " \"5x%5E2%2B-5x%2B1+=+5%28x-0.723606797749979%29%2A%28x-0.276393202250021%29\"
\n" ); document.write( " Again, the answer is: 0.723606797749979, 0.276393202250021.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B-5%2Ax%2B1+%29\"

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