document.write( "Question 972254: Three trains start at different times on a 100 mile journey.Train A leaves late and stops at a station for 5 minutes.its average speed is 40mph.Train B leaves 20 minutes late and stops at a station for 14 minutes. its average speed is 50mph. Train c leaves 30 minutes late and stops at a station for 10 minutes.its average speed is 50mph.which train completes the journey in the shortest time \n" ); document.write( "
Algebra.Com's Answer #594596 by Theo(13342)![]() ![]() You can put this solution on YOUR website! there may be a few ways to calculate this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let's try this one.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "train B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when it is moving, train B travels at 50 mph. \n" ); document.write( "100 miles divided by 50 miles per hour is 2 hours. \n" ); document.write( "train B left 20 minutes late and stopped at a station for 14 minutes. \n" ); document.write( "20 + 14 = 34 minutes divided by 60 minutes per hour = 34/60 hours \n" ); document.write( "take 2 hours and add 34/60 hours and you get 2 hours and 34/60 hours total time for train B to travel 100 miles. \n" ); document.write( "this is equivalent to 2.57 hours.\r \n" ); document.write( "\n" ); document.write( "train C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when it is moving, train C travels at 50 mph. \n" ); document.write( "100 miles divided by 50 miles per hour is 2 hours. \n" ); document.write( "train C left 30 minutes late and stops at a station for 10 minutes. \n" ); document.write( "30 + 10 = 40 minutes divided by 60 minutes per hour = 40/60 hours. \n" ); document.write( "take 2 hours and add 40/60 hours and you get 2 hours and 40/60 hours total time for train C to travel 100 miles. \n" ); document.write( "this is equivalent to 2.67 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so far train B took less time overall.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "train A.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "train A leaves late, but you haven't said how late. \n" ); document.write( "that's a missing point of information for train A. \n" ); document.write( "it stops at a station for 5 minutes. \n" ); document.write( "it's average speed is 40 mph, when it is moving!!!!! \n" ); document.write( "this is a key assumption. \n" ); document.write( "average speed when it is moving is different than average speed overall. \n" ); document.write( "average speed overall includes the time it is not moving. \n" ); document.write( "the train that takes the longest time will have the lowest overall speed regardless of what speed it is traveling at when it is moving.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "train A would take 100/40 = 2.5 hours without any stops and without being late. \n" ); document.write( "train A stopped at a station for 5 minutes, so the total time it takes without being late is 2.5 + 5/60 hours. \n" ); document.write( "this is equivalent to 2.58 hours. \n" ); document.write( "you still need to add x hours to this for the number of hours that train A is late. \n" ); document.write( "it doesn't matter. \n" ); document.write( "even if train A left on time, it would not have the fastest time overall.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this analysis, train B takes the shortest time at 2.57 hours. \n" ); document.write( "train A, even if it was not late starting, took 2.58 hours.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |