document.write( "Question 82873: What is the slope of a line perpendicular to the line passing through (-2,6) and (0,10)?
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Algebra.Com's Answer #59457 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First lets find the slope of the line going through (-2,6) and (0,10)\r
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Solved by pluggable solver: Finding the slope

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\n" ); document.write( " Slope of the line through the points (-2, 6) and (0, 10)
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\n" ); document.write( " \"m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"
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\n" ); document.write( " \"m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+%28x%5B1%5D%29%29\"
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\n" ); document.write( " \"m+=+%2810+-+6%29%2F%280+-+%28-2%29%29\"
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\n" ); document.write( " \"m+=+%2810+-+6%29%2F%280+%2B+2%29\"
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\n" ); document.write( " \"m+=+%284%29%2F%282%29\"
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\n" ); document.write( " \"m+=+2\"
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\n" ); document.write( " Answer: Slope is \"m+=+2\"
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\n" ); document.write( "\n" ); document.write( "Remember, perpendicular slopes are always the negative reciprocal of each other. In other words we have\r
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\n" ); document.write( "\n" ); document.write( "\"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope\r
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\n" ); document.write( "\n" ); document.write( "so plug in the slope we solved for to find the perpendicular slope:\r
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\n" ); document.write( "\n" ); document.write( "\"m%5Bp%5D=-1%2F2\" Plug in m=2\r
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\n" ); document.write( "\n" ); document.write( "So the perpendicular slope is \"-1%2F2\"\r
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