document.write( "Question 972141: the value of an antique car is modeled by the function V(x) = 1007,000(1.009)^(2.3x) where x is the number of years since 2005. By what approximate percent rate is the value of the car increasing per year? \n" ); document.write( "
Algebra.Com's Answer #594564 by josmiceli(19441)\"\" \"About 
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In the year 2005, \"+x+=+0+\"
\n" ); document.write( "Anytyhing to the zero power is \"+1+\", so
\n" ); document.write( "\"+V%28x%29+=+1007000%2A1.009%5E%282.3x%29+\"
\n" ); document.write( "\"+V%280%29+=+1007000%2A1.009%5E%282.3%2A0%29+\"
\n" ); document.write( "\"+V%280%29+=+1007000+\"
\n" ); document.write( "and
\n" ); document.write( "\"+V%281%29+=+1007000%2A1.009%5E%282.3%2A1%29+\"
\n" ); document.write( "Can't find calculator
\n" ); document.write( "Find \"+V%281%29+-+V%280%29+\"
\n" ); document.write( "\"+%28+V%281%29+-+V%280%29+%29+%2F+V%280%29+\" is the fraction of the increase
\n" ); document.write( "Multiply this by \"+100+\" to get the percent increase
\n" ); document.write( "for 1 year\r
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