document.write( "Question 972136: Please help me solve this word problem.
\n" ); document.write( "A rowing crew practices at a steady rate of 9 miles per hour. When they practice in steadily flowing river, a 10-mile trip downstream takes the same time as a 5-mile trip upstream. What is the rate of the river current?\r
\n" ); document.write( "\n" ); document.write( "I have tried 9/10 = 0.9
\n" ); document.write( "I have tried dividing 9/5 = 1.8
\n" ); document.write( "I have tried (10+5)/9 = 1.7
\n" ); document.write( "I have tried (9*10)/5 = 18
\n" ); document.write( "I have tried 9=10/x ~ 9/10 =.9 ~ .9*5 = 4.5\r
\n" ); document.write( "\n" ); document.write( "I do not know how to figure out the answer. It would be helpful if i could have a formula for solving the problem.
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Algebra.Com's Answer #594515 by iloveblacky123(1)\"\" \"About 
You can put this solution on YOUR website!
C = rate of current
\n" ); document.write( "so basically you are cross multiplying \"10%2F%289%2Bc%29+=+5%2F%289-c%29\"
\n" ); document.write( "cross multiply \"10%2A%289-c%29\"
\n" ); document.write( "which equals \"90-10c\"
\n" ); document.write( "cross multiply \"%289%2Bc%29%2A5\"
\n" ); document.write( "which equals \"45%2B5c\"
\n" ); document.write( "\"90-10c+=+45%2B5c\"
\n" ); document.write( "\"90-45+=+45\"
\n" ); document.write( "\"10c%2B5c+=+15c\"
\n" ); document.write( "\"45+=+15c\"
\n" ); document.write( "\"45%2F15+=+c\"
\n" ); document.write( "\"3=c\"
\n" ); document.write( "the answer for rate of current is 3
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