document.write( "Question 82748: A painting measuring 12 inches by 18 inches is surrounded by a frame of uniform width. If the combined area of the painting and the frame is 432 square inches, determine the width of the frame. \n" ); document.write( "
Algebra.Com's Answer #59451 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! (12+2x)(18+2x)=432 \n" ); document.write( "216+36x+24x+4x^2=432 \n" ); document.write( "4x^2+60x+216-432=0 \n" ); document.write( "4x^2+60x-216=0 \n" ); document.write( "x^2+15x-54=0 \n" ); document.write( "(x-18)(x+3)=0 \n" ); document.write( "x-18=0 \n" ); document.write( "x=18 not an answer. \n" ); document.write( "x-3=0 \n" ); document.write( "x=3 answer for the width of the frame. \n" ); document.write( "proof \n" ); document.write( "(12+6)(18+6)=432 \n" ); document.write( "18*24=432 \n" ); document.write( "432=432\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |