document.write( "Question 972136: Please help me solve this word problem.
\n" ); document.write( "A rowing crew practices at a steady rate of 9 miles per hour. When they practice in steadily flowing river, a 10-mile trip downstream takes the same time as a 5-mile trip upstream. What is the rate of the river current?\r
\n" ); document.write( "\n" ); document.write( "I have tried 9/10 = 0.9
\n" ); document.write( "I have tried dividing 9/5 = 1.8
\n" ); document.write( "I have tried (10+5)/9 = 1.7
\n" ); document.write( "I have tried (9*10)/5 = 18
\n" ); document.write( "I have tried 9=10/x ~ 9/10 =.9 ~ .9*5 = 4.5\r
\n" ); document.write( "\n" ); document.write( "I do not know how to figure out the answer. It would be helpful if i could have a formula for solving the problem.
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Algebra.Com's Answer #594502 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
speed= rowing speed + current or - current
\n" ); document.write( "r=rowing speed, c=current
\n" ); document.write( "distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "10=9t +ct, where t=time t= 10/(9+c)
\n" ); document.write( "5=9t-ct, because it is the same time t=5/(9-c)\r
\n" ); document.write( "\n" ); document.write( "[10/(9+c)]=[5/(9-c)]\r
\n" ); document.write( "\n" ); document.write( "cross-multiply\r
\n" ); document.write( "\n" ); document.write( "90-10c=45 +5c
\n" ); document.write( "45=15c
\n" ); document.write( "3=c\r
\n" ); document.write( "\n" ); document.write( "speed downstream is 12 mph, and it takes (10/12) hours to cover 10 miles
\n" ); document.write( "speed upstream is 6 mph, and it takes (5/6) hours to cover 5 miles. Those fractions are equivalent.
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