document.write( "Question 972110: Please help! Sorry it's more than one question
\n" ); document.write( "A ball is thrown straight up with an initial velocity of 40 m/s, so that its height (in meters) after t seconds is: h(t) = 2t(20 − t).\r
\n" ); document.write( "\n" ); document.write( "(a) Find an expression for the velocity of the ball at time t.\r
\n" ); document.write( "\n" ); document.write( "(b) What is the instantaneous velocity at t = 4? Is the ball rising or falling at this time?\r
\n" ); document.write( "\n" ); document.write( "(c) What is the maximum height achieved by the ball? Hint: the velocity of the ball will be zero when the ball is at its highest point.\r
\n" ); document.write( "\n" ); document.write( "(d) How fast will the ball be travelling when it hits the ground? Hint: first calculate time t when the ball hits the ground.
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Algebra.Com's Answer #594487 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
velocity(v) is defined as the first derivative of the position function
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\n" ); document.write( "h(t) = 2t(20 − t) = 40t - 2t^2
\n" ); document.write( "note that this is a parabola that opens downward
\n" ); document.write( "v = h'(t) = 40 - 4t
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\n" ); document.write( "a) v = h'(t) = 40 - 4t
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\n" ); document.write( "b) v = 40 - (4*4) = 24
\n" ); document.write( "ball is rising
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\n" ); document.write( "c) 0 = 40 - 4t
\n" ); document.write( "-4t = -40
\n" ); document.write( "t = 10 and
\n" ); document.write( "h(10) = 40t - 2t^2
\n" ); document.write( "h(10) = 400 - 200 = 200
\n" ); document.write( "max height is 200 m
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\n" ); document.write( "d) 0 = 40t - 2t^2
\n" ); document.write( "2t^2 = 40t
\n" ); document.write( "t = 20 and
\n" ); document.write( "h'(20) = 40 - 4*20
\n" ); document.write( "h'(20) = -40 which is a downward velocity of 40 m/s\r
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