document.write( "Question 82853: A circle is defined by the following equation :\r
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document.write( " 3x^2+3y^2-24x+42y+183=0\r
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document.write( " What is the radius? \n" );
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Algebra.Com's Answer #59448 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! A circle is defined by the following equation :\r \n" ); document.write( "\n" ); document.write( " 3x^2+3y^2-24x+42y+183=0\r \n" ); document.write( "\n" ); document.write( " What is the radius? \n" ); document.write( "The standard form of the equation of a circle is \n" ); document.write( "First divide the whole equation by 3 because x^2 and y^2 have to have a coefficient of 1 in order to be in standard form. \n" ); document.write( "3x^2/3+3y^2/3-24x/3+42y/3+183/3=0/3 \n" ); document.write( "x^2+y^2-8x+14y+61=0 \n" ); document.write( "Group the x terms and y terms and subtract 61 from both sides of the equation \n" ); document.write( "x^2-8x+__+y^2+14y+___=-61+___+___ \n" ); document.write( "We need to complete the square by taking half of the coefficients of x and y and squaring them and adding them to both sides of the equation. \n" ); document.write( "x^2-8x+(-8/2)^2+y^2+14y+(14/2)^2=-61+(-8/2)^2+(14/2)^2 \n" ); document.write( "x^2-8x+(-4)^2+y^2+14y+(7)^2=-61+(-4)^2+(7)^2 \n" ); document.write( "(x-4)^2+(y+7)^2=-61+16+49 \n" ); document.write( "(x-4)^2+(y+7)^2=4 \n" ); document.write( "(x-4)^2+(y+7)^2=2^2 \n" ); document.write( "The radius is 2 \n" ); document.write( "You didn't ask for the center, but it's (4,-7) \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |