document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972087>Question 972087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the sum of (2/3) + (2/3)^2 + (2/3)^3 + (2/3)^4 +....+ (2/3)^100 ?\r<BR>\n" );
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document.write( "I think the answer is 2-2(2/3)^100\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594479 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Hello,\r<BR>\n" );
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document.write( "Using the rule <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28p%2Fq%29%5En+=++p%5En%2Fq%5En ALIGN=MIDDLE  ALT=\"%28p%2Fq%29%5En+=++p%5En%2Fq%5En\"   DISABLED_style= \"max-width:90%; height:auto;\" > we have (2/3)^n \r<BR>\n" );
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document.write( "where n represents the exponents 1, 2, 3, 4, +... +, 100. So for,\r<BR>\n" );
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document.write( "The sum of (2/3) + (2/3)^2 + (2/3)^3 + (2/3)^4 +....+ (2/3)^100 will be as follows:\r<BR>\n" );
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document.write( "and the decimal approximation is 1.99999...\r<BR>\n" );
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document.write( "Your answer 2-2(2/3)^100 is correct. \r<BR>\n" );
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