document.write( "Question 972085: \"8+=+4%5E%28x%5E2%29%2A2%5E%285x%29\" Solve for x. \n" ); document.write( "
Algebra.Com's Answer #594468 by josgarithmetic(39618)\"\" \"About 
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\"8+=+4%5E%28x%5E2%29%2A2%5E%285x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E3=%282%5E2%29%5E%28x%5E2%29%2A2%5E%285x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E3=%282%5E%282x%5E2%29%29%2A2%5E%285x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E3=2%5E%282x%5E2%2B5x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Same base of 2 on both sides, so their exponents are equal:\r
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\n" ); document.write( "\n" ); document.write( "\"3=2x%5E2%2B5x\"------More easily solvable in this form now.\r
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\n" ); document.write( "You should at least obtain a quadratic equation equivalent to the one shown there.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B5x-3=0\"
\n" ); document.write( "discriminant is \"25%2B8%2A3=25%2B24=49=7%5E2\".
\n" ); document.write( "The quadratic part is factorable.(?)
\n" ); document.write( "\"x=%28-5%2B-+7%29%2F4\"
\n" ); document.write( "x=-3 or x=1/2\r
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\n" ); document.write( "\n" ); document.write( "or,
\n" ); document.write( "\"%282x-1%29%28x%2B3%29=0\"
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