document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972080>Question 972080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 times longer than its width. If the diagonal of the rectangle measures 21 inches, what is its length? Type your answer as a decimal rounded to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594466 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width of the rectangle be x.<BR>\n" );
document.write( "Then the length of the rectangle is 2x.<BR>\n" );
document.write( "Diagonal of the rectangle =21 inches<BR>\n" );
document.write( "Applying Pythagoras theorem,<BR>\n" );
document.write( "(Diagonal)^2=(length)^2+(width)^2<BR>\n" );
document.write( "x^2+(2x)^2=21^2<BR>\n" );
document.write( "x^2+4x^2=441<BR>\n" );
document.write( "5x^2=441<BR>\n" );
document.write( "x^2=441/5=88.2<BR>\n" );
document.write( "x=9.391485505499117<BR>\n" );
document.write( "length=2x=18.78297101099823<BR>\n" );
document.write( "The length of the rectangle is 18.783 inches\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );