document.write( "Question 972068: solve for x: 2^(x-1) = 3^(2x+1) Answer is: Log2+log3/log2-2log3 = -1.191
\n" ); document.write( "Please help to arrive at answer.
\n" ); document.write( "Thank you!
\n" ); document.write( "Tiffany
\n" ); document.write( "

Algebra.Com's Answer #594460 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%5E%28x-1%29+=+3%5E%282x%2B1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%28%282%5E%28x-1%29%29%29+=+log%28%283%5E%282x%2B1%29%29%29\" Apply logs to both sides (to isolate exponents)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%2Alog%28%282%29%29+=+%282x%2B1%29%2Alog%28%283%29%29\" Use rule 3 (from this link)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%28%282%29%29-log%28%282%29%29+=+2x%2Alog%28%283%29%29%2Blog%28%283%29%29\" Distribute\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%28%282%29%29+=+2x%2Alog%28%283%29%29%2Blog%28%283%29%29%2Blog%28%282%29%29\" Add \"log%28%282%29%29\" to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%28%282%29%29-2x%2Alog%28%283%29%29+=+log%28%283%29%29%2Blog%28%282%29%29\" Subtract \"2x%2Alog%28%283%29%29\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%28log%28%282%29%29-2%2Alog%28%283%29%29%29+=+log%28%283%29%29%2Blog%28%282%29%29\" Factor out the GCF x\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28log%28%283%29%29%2Blog%28%282%29%29%29%2F%28log%28%282%29%29-2%2Alog%28%283%29%29%29\" Divide both sides by \"log%28%282%29%29-2%2Alog%28%283%29%29\" to isolate x.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28log%28%282%29%29%2Blog%28%283%29%29%29%2F%28log%28%282%29%29-2%2Alog%28%283%29%29%29\" Rearrange terms. This is the exact answer in terms of logs.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+-1.19126813092756\" Use a calculator to get the approximate answer\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+-1.191\" Round to 3 decimal places (again this is approximate)
\n" ); document.write( "
\n" );