document.write( "Question 972064: How to solve for X: Log(base3) (x-4) = 2 - log(base3) (x+4) Answer given is \"x=5\" Could you please explain how to arrive at 5?
\n" ); document.write( "Thank you,
\n" ); document.write( "Tiffany
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Algebra.Com's Answer #594457 by Boreal(15235)\"\" \"About 
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Log(base3) (x-4) = 2 - log(base3) (x+4)
\n" ); document.write( "log 3 (x-4) + log 3(x+4) =2\r
\n" ); document.write( "\n" ); document.write( "log 3{ (x-4)*(x+4)}=2 When you add logs, it is multiplication if you combine them with the same base.\r
\n" ); document.write( "\n" ); document.write( "log 10 (100) + log 10 (10)= log 10 (1000)=3 The left side is 2+1=3
\n" ); document.write( "Raise both to the 3 power. The log goes away.\r
\n" ); document.write( "\n" ); document.write( "(x-4)*(x+4)=9\r
\n" ); document.write( "\n" ); document.write( "x^2-16=9
\n" ); document.write( "x^2=25
\n" ); document.write( "x+ +5 -5 is extraneous. \r
\n" ); document.write( "\n" ); document.write( "Check log 3 (1)=2 - log 3 (9)
\n" ); document.write( "The left side is 0 (3^0=1)
\n" ); document.write( "The right side is 2-2=0\r
\n" ); document.write( "\n" ); document.write( "Checks
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