document.write( "Question 972050: I need help with this problem:\r
\n" ); document.write( "\n" ); document.write( "The number of bacteria in a certain culture increased from 600 to 1800 between 7:00am and 9:00am. Assuming growth is exponential, the number of f(t) bacter1a t hours after 7:00am is given by f(t)=600(3)^(t/2).\r
\n" ); document.write( "\n" ); document.write( "a. Estimate the number of bacteria in the culture at 8:00am, 10:00am, and 11:00am.\r
\n" ); document.write( "\n" ); document.write( "b. Sketch the graph of f for 0<=t<=4.\r
\n" ); document.write( "\n" ); document.write( "Any help would be greatly appreciated.
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Algebra.Com's Answer #594454 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
at 1 hour f(1)=600* 3^(1/2)=1039
\n" ); document.write( "at 3 hours f(3)=600* 3 ^(3/2)=3118
\n" ); document.write( "at 4 hours f(4)=600*3 ^(4/2)=5400\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-1%2C5%2C-5%2C6000%2C600%2A3%5E%28x%2F2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Ignore the negatives on the graph. It formats better if I put them in.
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