document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972027>Question 972027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three times a number and twice another number is 120. Twice the first number plus four times the other number is 65. Calculate the values of the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594426 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> number is x; other number is y\r<BR>\n" );
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document.write( "3x +2y=120<BR>\n" );
document.write( "2x +4y=65\r<BR>\n" );
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document.write( "Multiply top by (-2)<BR>\n" );
document.write( "-6x -4y =-240<BR>\n" );
document.write( "2x +4y  =65   Add them\r<BR>\n" );
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document.write( "-4x =-175<BR>\n" );
document.write( "x=43.75<BR>\n" );
document.write( "2x+4y=87.5 +4y+65\r<BR>\n" );
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document.write( "4y= -22.5<BR>\n" );
document.write( "y= -5.625\r<BR>\n" );
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document.write( "3(43.75) + 2(-5.625)= 131.25 - 11.25=120<BR>\n" );
document.write( "2(43.75) +4 (-5.625) =87.5-22.5 =65\r<BR>\n" );
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document.write( "(43.75, -5.625) </SPAN>\n" );
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