document.write( "Question 82851: A circle is defined by the following equation:\r
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document.write( " 2x^2+2y^2+28x+80=0\r
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document.write( "What is the radius? \n" );
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Algebra.Com's Answer #59439 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! A circle is defined by the following equation:\r \n" ); document.write( "\n" ); document.write( " 2x^2+2y^2+28x+80=0\r \n" ); document.write( "\n" ); document.write( "What is the radius? \n" ); document.write( "The standard form of the equation of a circle is: \n" ); document.write( "First divide everything by 2 because x^2 and y^2 have to have 1 as their coefficients. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now get the x's next to each other the y's next to each other and the constants on the other side of the = sign: \n" ); document.write( "x^2+14x+y^2+40-40=0-40 \n" ); document.write( "x^2+14x+y^2=-40 \n" ); document.write( "Now complete the square for the x terms. Add 1/2 the coefficient of x squared to both sides of the =sign. \n" ); document.write( "x^2+14x+(14/2)^2+y^2=-40+(14/2)^2 \n" ); document.write( "x^2+14x+(7)^2+y^2=-40+(7)^2 \n" ); document.write( "x^2+14x+49+y^2=-40+49 \n" ); document.write( "(x^2+14x+49)+y^2=9 \n" ); document.write( "(x+7)^2+(y-0)^2=3^2 \n" ); document.write( "The radius is 3. \n" ); document.write( "You didn't ask for the center, but it's (-7,0) \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |