document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971955>Question 971955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A metal worker has a metal alloy that is 30% copper and another alloy that is 80% copper. How many kilograms of each alloy should the metalworker combine to creat 60 kilograms of a 51% copper alloy?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594382 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A metal worker has a metal alloy that is 30% copper and another alloy that is 80% copper. How many kilograms of each alloy should the metalworker combine to creat 60 kilograms of a 51% copper alloy?<BR>\n" );
document.write( "let x=amt of 30% copper alloy to combine<BR>\n" );
document.write( "60-x=amt of 80% copper alloy to combine<BR>\n" );
document.write( "..<BR>\n" );
document.write( "30%x+80%(60-x)=51%*60<BR>\n" );
document.write( ".30x+40-.80x=30.6<BR>\n" );
document.write( ".50x=9.4<BR>\n" );
document.write( "x=50.6<BR>\n" );
document.write( "How many kilograms of each alloy should the metalworker combine?<BR>\n" );
document.write( "30% copper alloy: 9.4 kg<BR>\n" );
document.write( "80% copper alloy: 50.6 kg </SPAN>\n" );
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