document.write( "Question 82755: Three consecutive evenintegers are such that the square of the third is 76 more than the square of the seconf. Find the three integers.\r
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Algebra.Com's Answer #59436 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
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\n" ); document.write( "Let x = 2nd consecutive number
\n" ); document.write( "Then (x+2) = 3rd consecutive number
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\n" ); document.write( "\"the third is 76 more than the square of the second.\" which can be written:
\n" ); document.write( "(x+2)^2 = 76 + x^2
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\n" ); document.write( "x^2 + 4x + 4 = x^2 + 76
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\n" ); document.write( "x^2 - x^2 + 4x = 76 - 4
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\n" ); document.write( "4x = 72
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\n" ); document.write( "x = 72/4
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\n" ); document.write( "x = 18 is the 2nd even consecutive number
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\n" ); document.write( "16, 18, 20 are the numbers
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\n" ); document.write( "Check on a calc: 20^2 - 18^2 = 76
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