document.write( "Question 971923: A survey found that people keep their televisions an average of 5.2 years. The standard deviation is 0.8 year. Assume the random variable is normally distributed. If you buy a TV for your dorm room and keep it for 3.8 years of school then sell it, what percentile does that put you in? \n" ); document.write( "
Algebra.Com's Answer #594356 by Boreal(15235)\"\" \"About 
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z=(sample -µ)/sd\r
\n" ); document.write( "\n" ); document.write( "z=(3.8-5.2)/0.8 ; This = -1.4/0.8 = - 1.571\r
\n" ); document.write( "\n" ); document.write( "I want z value to the left of -1.571
\n" ); document.write( "That is 0.058 or the 6th percentile.
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