document.write( "Question 971926: An amount of money invested for 1 year in a savings account will earn $800. That same amount of money invested in a mini-mall development will earn $2,800 interest in a year, because the interest paid is 10% more than that paid by the savings account. Find the rate of interest paid by each investment. \n" ); document.write( "
Algebra.Com's Answer #594340 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=amount of money in saving's account; y=interest rate.\r \n" ); document.write( "\n" ); document.write( "x* y=800 \n" ); document.write( "x*(y+0.10)=2800; xy + 0.10x=2800\r \n" ); document.write( "\n" ); document.write( "y=800/x\r \n" ); document.write( "\n" ); document.write( "800 +0.10 x=2800 \n" ); document.write( "0.10x =2000 \n" ); document.write( "multiply by 10\r \n" ); document.write( "\n" ); document.write( "x=$20000\r \n" ); document.write( "\n" ); document.write( "800/20000=4%\r \n" ); document.write( "\n" ); document.write( "14% on 20,000=$2800 Check\r \n" ); document.write( "\n" ); document.write( "Rate of interest is 4% on savings and 14% on mini-mall. \n" ); document.write( " |