document.write( "Question 82845: using the exact values find the numerical value of
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document.write( "a. sin 30degrees cos 240degrees + sin 210degrees sin 300degrees
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document.write( "b. tan 225degrees + tan (-45degrees) \n" );
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Algebra.Com's Answer #59432 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! using the exact values find the numerical value of \n" ); document.write( "a. sin 30degrees cos 240degrees + sin 210degrees sin 300degrees \n" ); document.write( "sin 30=1/2 \n" ); document.write( ": \n" ); document.write( "cos 240 is in QIII, so it's negative and has a reference angle of 240-180=60, cos 60=1/2, therefore the cos 240=-1/2 \n" ); document.write( ": \n" ); document.write( "sin 210 is in QIII, so it's negative and has a reference angle of 210-180=30, sin 30=1/2, therefore sin 210=-1/2 \n" ); document.write( "sin 300 is in QIV, so it's negative and has a reference angle of 360-300=60, sin 60=sqrt(3)/2, therefore sin 300=-sqrt(3)/2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "b. tan 225degrees + tan (-45degrees) \n" ); document.write( "tan 225 is in QIII which is positive for tan and has a reference angle of 225-180=45, tan 45 = 1, therefore tan 225=1 \n" ); document.write( ": \n" ); document.write( "tan -45 is in QIV which is negative for tan and has a reference angel of 45, tan 45 =1 , therefore tan -45=-1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |